ЗДравейте, сайтът е: www.shareit.bg и на страница излиза грешка която не можем да я оправим:

Кода и:

<?
include 'include.php';
top('On the top');
db_init();
function checkIsFriend($otherID){
//AND friendtoadd='.$otherID.'' AND userfrom='.$otherID.''
$q=mysql_query('SELECT * FROM shareit_friends WHERE userfrom='.$_SESSION['ui']['id'].'AND friendtoadd='.$otherID.'');
echo mysql_error();
$q1=mysql_query('SELECT * FROM shareit_friends WHERE friendtoadd='.$_SESSION['ui']['id'].'AND userfrom='.$otherID.'');
if (mysql_num_rows($q)!=0 || mysql_num_rows($q1)!=0){
$added=1;
}
else{
$added=0;
}
echo mysql_error();
return $added;
}
$r=intval($_GET['id']);
echo checkIsFriend($r);
?>

Грешка:

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'AND friendtoadd=15164' at line 1You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'AND userfrom=15164' at line 10

Помогнете, спешно е да оправим грешката!

На пръв поглед виждам, че нямаш интервал пред AND.

$q=mysql_query('SELECT * FROM shareit_friends WHERE userfrom="'.$_SESSION['ui']['id'].'" AND friendtoadd="'.$otherID.'"');
//echo mysql_error();
$q1=mysql_query('SELECT * FROM shareit_friends WHERE friendtoadd="'.$_SESSION['ui']['id'].'" AND userfrom="'.$otherID.'"');

въздържайте се от *, а посочете името конкретното.